# Difference between revisions of "Computer Number Systems"

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\$ABDE_{16}\$

All computers – from large mainframes to hand-held micros – ultimately can do one thing: detect whether an electrical signal is “on” or “off”. Computer programs in all high-level languages are converted by various pieces of systems software into sequences of bits (Binary digITs) which correspond to sequences of on/off (equivalently TRUE/FALSE or 1/0) signals. These bits must represent the operation and the address for each instruction. Binary digits (or bits) are also used to represent all forms of data including integers, floating point or decimal values, character strings, sound, and visual images. Proficiency in the binary number system is essential to understanding how a computer works.

Since binary numbers representing moderate values quickly become rather lengthy, bases eight (octal) and sixteen (hexadecimal) are frequently used as short-hand. Octal numbers group binary numbers in bunches of 3 digits and convert the triplet to a single digit between 0 and 7, inclusive.

For example, 10010101102 = 001 001 010 1102 = 11268.

This is because 8 = 23 and the value of three bits 111 = 1 + 2 + 4 = 7 using powers of 2.

Hexadecimal numbers group binary numbers by fours, and convert the quadruplet to a single digit in the range 0, 1, 2 …, 9, A, B, C, D, E, F. The digits A through F have decimal values of 10 through 15 respectively. This is because 16 = 24 and the value of four bits 1111 = 1 + 2 + 4 + 8 = 15 using powers of 2.

For example, 101101101001012 = 0010 1101 1010 01012 = 2DA516.

All of the basic rules of number theory apply to every base, but these three bases 2, 8, and 16 are uniquely suited for computer science.

Therefore, converting from any base to base 10 involves multiplying each digit by an increasing power of that base.

For example, 4578 = 7 x 80 + 5 x 81 + 4 x 82 = 7 + 40 + 256 = 30310.

Converting from base 10 to any other base involves finding how many times each decreasing power of that base can be divided evenly into the number and repeating the process with the remainder. For example, 50010 = 256 x 1 + 16 x 15 + 1 x 4 = 1F416. Another way to accomplish this is to repeatedly divide the number by the base as follows:

Therefore, reading the remainders from bottom to top give you 1F416.

Adding in bases other than 10 means that you must carry the value of that base and subtracting in bases other than 10 means that you must borrow the value of that base if necessary. For example:

since D=13 and 13+3=16 so leave the 0 and carry the 16 as a 1. Then E=14 and A=10 so 1+14+10 = 25 so leave the 9 and carry the 16 as a 1. E=14 so 1+14+9=24 so leave the 8 and carry the 16 as 1. Finally, F=15 so 1+15=16 which is 10.

Subtracting in base 8 is as follows:

Borrow 1=8 from the 7 since 2+8-6=4. Therefore, 6–5=1. Then, borrow 1=8 from the 4 since 5+8–7=6. Then the last digit on the left is a 3.

## Format of Problems

The key here is to convert between hexadecimal (base 16) and octal (base 8); using the binary representation is often easier than going through base 10. Some problems require simple arithmetic in hexadecimal and octal, and once in a while you’ll see of “decimal point”. 1)Facts you must know cold: a. The values of hex digits A, B, C, D, E, F b.Powers of 2, up to, say, 4096 c.Powers of 8, up to say, 4096 d.Powers of 16, up to say, 65,536 e.Convert from base 16 to base 2, and vice versa f.Convert from base 8 to base 2, and vice versa

Binary Tutorial - 1. Number Systems https://ryanstutorials.net/binary-tutorial/

https://ryanstutorials.net/binary-tutorial/binary-conversions.php Binary Tutorial - 2. Binary Conversions

Binary Tutorial - 3. Binary Arithmetic https://ryanstutorials.net/binary-tutorial/binary-arithmetic.php

Binary Tutorial - 5. Binary Fractions and Floating Point https://ryanstutorials.net/binary-tutorial/binary-floating-point.php